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A.E.E2 EB9 Maths Noel 2011

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Posted on January 8, 2012 Full Size| Slideshow

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7 Comments

wassim abdel nour
1:43 PM on January 14, 2012 
tu dois donner la valeur me "m" non de "-m"
wassim abdel nour
1:39 PM on January 14, 2012 
on a pas demande la valeur de "x" en plus il est impossible de la calculer
wassim abdel nour
1:01 PM on January 14, 2012 
tu as mal copie la donnee de Q(x)
claudia sa
11:48 AM on January 14, 2012 
m=-14
mazenhabib
3:08 PM on January 13, 2012 
REGARDEZ LA DONNEE!!!!
Q( x ) = ?????? ..
claudia sa
12:57 PM on January 8, 2012 
m=16 :D
mazenhabib
11:58 AM on January 8, 2012 
P(X) et Q(X) doivent avoir la meme forme reduite.
donc, en developpant Q( x ) on aura :
Qx)=16x^2-8x+1-m
or, P( x) = 16x^2 -8x +15
donc, tu peux maintenant deduire la valeur de m?

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