A.E.E2 EB9 Maths Noel 2011

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Posted on January 9, 2012

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6 Comments

maguy akl

2:15 PM on January 14, 2012

comme a dit antony la reponse devait etre (2x+3)(2x-5)

anthony abi nader

11:49 AM on January 14, 2012

(2x+3)(2x-5) est la bonne reponse enfin de factorisation

Christelle Gulgulian

11:26 AM on January 14, 2012

Oui .. et puis elle aura un facteur commun.

mazenhabib

3:23 PM on January 13, 2012

continue la factorisation Maguy!

maguy akl

9:18 AM on January 13, 2012

c'est une identitée remarquable de la forme a^2 -b^2 donc ( 4x -1 )^2 -16 = (2x -1+4)(2x-1-4)

mazenhabib

3:08 PM on January 9, 2012

Maguy, P et Q sont identiques donc P(x) = Q( x) ce qui est vrai chez toi.
Ainsi, factoriser Q(x) revient a factoriser P(x).
or, P( x) = ( 4x -1 )^2 -16 donc ????? j'attends la reponse

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