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A.E.E2 EB9 Maths Noel 2011

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Posted on January 9, 2012 Full Size| Slideshow

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6 Comments

maguy akl
2:15 PM on January 14, 2012 
comme a dit antony la reponse devait etre (2x+3)(2x-5)
anthony abi nader
11:49 AM on January 14, 2012 
(2x+3)(2x-5) est la bonne reponse enfin de factorisation
Christelle Gulgulian
11:26 AM on January 14, 2012 
Oui .. et puis elle aura un facteur commun.
mazenhabib
3:23 PM on January 13, 2012 
continue la factorisation Maguy!
maguy akl
9:18 AM on January 13, 2012 
c'est une identitée remarquable de la forme a^2 -b^2 donc ( 4x -1 )^2 -16 = (2x -1+4)(2x-1-4)
mazenhabib
3:08 PM on January 9, 2012 
Maguy, P et Q sont identiques donc P(x) = Q( x) ce qui est vrai chez toi.
Ainsi, factoriser Q(x) revient a factoriser P(x).
or, P( x) = ( 4x -1 )^2 -16 donc ????? j'attends la reponse

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